search
Categories
Sponsors
VirtualMetric Hyper-V Monitoring, Hyper-V Reporting
Archive
Blogroll

Badges
MCSE
Community

Cozumpark Bilisim Portali
Get Directory Content and Output it as HTML with Powershell
Posted in Windows Powershell | No Comment | 5,460 views | 14/07/2012 21:56

You may need to get a directory content and output it as HTML.

Here is an example code of PoSHServer:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
function Get-DirectoryContent
{
param ($Path, $HeaderName, $RequestURL, $SubfolderName)
@"
<html>
<head>
<title>$($HeaderName)</title>
</head>
<body>
<h1>$($HeaderName) - $($SubfolderName)</h1>
<hr>
"@
$ParentDirectory = $RequestURL + $Subfoldername + "../"
@"
<a href="$($ParentDirectory)">[To Parent Directory]</a><br><br>
<table cellpadding="5">
"@
$Files = (Get-ChildItem "$Path")
foreach ($File in $Files)
{
$FileURL = $RequestURL + $Subfoldername + $File.Name
if (!$File.Length) { $FileLength = "[dir]" } else { $FileLength = $File.Length }
@"
<tr>
<td align="right">$($File.LastWriteTime)</td>
<td align="right">$($FileLength)</td>
<td align="left"><a href="$($FileURL)">$($File.Name)</a></td>
</tr>
"@
}
@"
</table>
<hr>
</body>
</html>
"@
}

It’s really like IIS outputs :)



Leave a Reply